Answer
$f(x^{2})=x^{2}+4$
$(f(x))^{2}=x^{2}+8x+16$
Work Step by Step
We are given:
$f(x)=x+4$
We evaluate:
$f(x^{2})=x^{2}+4$
$(f(x))^{2}=(x+4)^{2}=x^{2}+8x+16$
College Algebra 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305115546
ISBN 13:
978-1-30511-554-5
Chapter 2, Functions - Section 2.1 - Functions - 2.1 Exercises - Page 193: 37
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