#### Answer

$f(x^{2})=x^{2}+4$
$(f(x))^{2}=x^{2}+8x+16$

#### Work Step by Step

We are given:
$f(x)=x+4$
We evaluate:
$f(x^{2})=x^{2}+4$
$(f(x))^{2}=(x+4)^{2}=x^{2}+8x+16$

Published by
Brooks Cole

ISBN 10:
1305115546

ISBN 13:
978-1-30511-554-5

$f(x^{2})=x^{2}+4$
$(f(x))^{2}=x^{2}+8x+16$

We are given:
$f(x)=x+4$
We evaluate:
$f(x^{2})=x^{2}+4$
$(f(x))^{2}=(x+4)^{2}=x^{2}+8x+16$

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