College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 2, Functions - Section 2.1 - Functions - 2.1 Exercises - Page 193: 42



Work Step by Step

We are given: $h(t)=t^{2}+5$ We evaluate: $h(-3)=(-3)^{2}+5=9+5=14$ $h(6)=6^{2}+5=36+5=41$ $h(6)-h(-3)=41-14=27$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.