# Chapter 2, Functions - Section 2.1 - Functions - 2.1 Exercises: 70

Domain: $(-\infty,\ 6)$

#### Work Step by Step

We are given: $f(x)= \frac{x^{2}}{\sqrt{6-x}}$ The domain of a function consists of all the values that $x$ is allowed to have. In this case, we can not take the square root of a negative number: $6-x\ge 0$ $6\ge x$ $x\le 6$ In addition, we can not have division by $0$: $6-x\ne 0$ $x\ne 6$ Therefore, the domain is: $(-\infty,\ 6)$

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