Answer
$f(x+2)=x^{2}+4x+5$
$f(x)+f(2)=x^{2}+6$
Work Step by Step
We are given:
$f(x)=x^2+1$
We evaluate:
$f(x+2)=(x+2)^{2}+1=x^{2}+4x+4+1=x^{2}+4x+5$
$f(x)+f(2)=x^{2}+1+(2)^{2}+1=x^{2}+1+4+1=x^{2}+6$
College Algebra 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305115546
ISBN 13:
978-1-30511-554-5
Chapter 2, Functions - Section 2.1 - Functions - 2.1 Exercises - Page 193: 35
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