#### Answer

$f(x+2)=x^{2}+4x+5$
$f(x)+f(2)=x^{2}+6$

#### Work Step by Step

We are given:
$f(x)=x^2+1$
We evaluate:
$f(x+2)=(x+2)^{2}+1=x^{2}+4x+4+1=x^{2}+4x+5$
$f(x)+f(2)=x^{2}+1+(2)^{2}+1=x^{2}+1+4+1=x^{2}+6$

Published by
Brooks Cole

ISBN 10:
1305115546

ISBN 13:
978-1-30511-554-5

$f(x+2)=x^{2}+4x+5$
$f(x)+f(2)=x^{2}+6$

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