## College Algebra 7th Edition

$(-\infty,\ 3)\cup (3,\ \infty)$
We are given: $f(x)= \frac{1}{x-3}$ The domain of a function consists of all the values that $x$ is allowed to have. In this case, $x$ can not equal $3$ because then we would have division by $0$. Thus the domain is: $(-\infty,\ 3)\cup (3,\ \infty)$