Answer
Point $Q(-1,3)$ is closer to point $R$ .
Work Step by Step
$d(P, R)=\sqrt{(-1-3)^{2}+(-1-1)^{2}}=\sqrt{(-4)^{2}+(-2)^{2}}$
$=\sqrt{16+4}=\sqrt{20}=2\sqrt{5}$.
$d(Q, R)=\sqrt{(-1-(-1))^{2}+(-1-3)^{2}}$
$=\sqrt{0+(-4)^{2}}=\sqrt{16}=4$.
$4<2\sqrt{5}$, so
point $Q(-1,3)$ is closer to point $R$ than point P.
