College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 1, Equations and Graphs - Section 1.1 - The Coordinate Plane - 1.1 Exercises - Page 92: 23


(a) $d=10$ (b) midpoint=$(1,0)$

Work Step by Step

(a) We find the distance between the two points $(-3,3)$ and $(5, -3)$ by using the distance formula: $d=\sqrt{(-3-5)^{2}+(3--3)^{2}}=\sqrt{(-8)^{2}+6^{2}}=\sqrt{64+36}=\sqrt{100}=10$ (b) We use the Midpoint Formula: midpoint=$(\displaystyle \frac{-3+5}{2},\ \frac{3+(-3)}{2})=(1,0)$
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