College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 1, Equations and Graphs - Section 1.1 - The Coordinate Plane - 1.1 Exercises - Page 92: 34

Answer

$S$ must be located at $(0, -4)$. Area = $50$.

Work Step by Step

See sketch. The point $S$ must be located at $(0, -4)$. To find the area, we find the length of one side and square it. $d(Q, R)=\sqrt{(-5-0)^{2}+(1-6)^{2}}=\sqrt{(-5)^{2}+(-5)^{2}}$ $=\sqrt{25+25}=\sqrt{50}$ $A= (\sqrt{50})^{2}=50$.
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