College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 1, Equations and Graphs - Section 1.1 - The Coordinate Plane - 1.1 Exercises: 22

Answer

(a) $d=5$ (b) midpoint=$(0,1/2)$

Work Step by Step

(a) We find the distance between the points $(-2,-1)$ and $(2,2)$ by using the Distance Formula: $d=\sqrt{(-2-2)^{2}+(-1-2)^{2}}=\sqrt{(-4)^{2}+(-3)^{2}}=\sqrt{16+9}=\sqrt{25}=5$ (b) We find the midpoint by using the Midpoint Formula: midpoint=$(\displaystyle \frac{-2+2}{2},\ \frac{-1+2}{2})=(0,\ \frac{1}{2})$
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