College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 1, Equations and Graphs - Section 1.1 - The Coordinate Plane - 1.1 Exercises: 24

Answer

(a) $d=2\sqrt{10}$ (b) midpoint=$(1,-2)$

Work Step by Step

(a) We find the distance between the two points $(-2, -3)$ and $(4, -1)$ by using the distance formula: (a) $d=\sqrt{(-2-4)^{2}+(-3--1)^{2}}=\sqrt{(-6)^{2}+(-2)^{2}}=\sqrt{36+4}=\sqrt{50}=2\sqrt{10}$ (b) We use the Midpoint Formula: midpoint=$(\displaystyle \frac{-2+4}{2},\ \frac{-3+-1}{2})=(1,\ -2)$
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