Answer
Area $=16$
Work Step by Step
Area = (base)$\times$(height)
With $\overline{AB}_{ }^{ }$ as base, parallel to the x-axis,
$d(A, B)=\sqrt{(1-5)^{2}+(2-2)^{2}}=\sqrt{(-4)^{2}}=4$.
We count the change in y coordinates as the height.
height= $6-2=4$.
Area $=4\cdot 4=16$
