## College Algebra (6th Edition)

$\frac{4}{x - 2}$, $x\ne2$
We must factor the top and bottom separately. First, we factor the top by pulling out a 4. Next, we factor the bottom as $(x - 2)(x - 2)$. The following results: $\frac{4(x-2)}{(x-2)(x-2)}$ Then, we are allowed to cancel out the $x - 2$ factors. This leads us to an answer of $\frac{4}{x - 2}$. Note that, since x = 2 is still a domain restriction (since it makes the denominator 0), we still must declare that $x\ne2$.