## College Algebra (6th Edition)

$\frac{x-2}{x-3}; x \ne 3,-2$
$=\frac{x^{2}-4x}{x^{2}-x-6} + \frac{4x-4}{x^{2}-x-6}$ Same denominator - add numerators. $=\frac{x^{2}-4x+4x-4}{x^{2}-x-6}$ Combine like terms. $=\frac{x^{2}-4}{x^{2}-x-6}$ Factor $=\frac{(x+2)(x-2)}{(x+2)(x-3)}; x \ne 3,-2;$ $=\frac{x-2}{x-3}; x \ne 3,-2$