College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter P - Prerequisites: Fundamental Concepts of Algebra - Exercise Set P.6 - Page 86: 24

Answer

$\frac{x+5}{7}\div\frac{4x+20}{9}$ $=\frac{x+5}{7}\times\frac{9}{4x+20}$ $=\frac{x+5}{7}\times\frac{9}{4(x+5)}$ $=\frac{1}{7}\times\frac{9}{4}$ $=\frac{9}{28}$

Work Step by Step

To divide rational expressions the first step is to invert the divisor and multiply. This is done by flipping the second fraction, $\frac{4x+20}{9}$ so that it becomes $\frac{9}{4x+20}$ and changing the division to multiplication. The next step is to factorise as many numerators and denominators as possible. In this case $4x+20$ can be factorised to $4(x+5)$ as the highest common multiple is $4$. The next step is to divide the common numerators and denominators so that they cancel out. $x+5$ is the only common numerator and denominator so they both cancel each other out. Because $x+5$ goes into $x+5$ once the numerator for the first fraction is $1$. The second fraction is left with a denominator of $4$. Lastly the two fractions are simplified to give the final answer.
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