Answer
$\frac{-3}{x(x+1)}; x\ne 0,-1;$
Work Step by Step
$\frac{3}{(x+1)} - \frac{3}{x}$
$= \frac{3x-3(x+1)}{x(x+1)} ; x \ne 0,-1;$
$= \frac{3x-3x-3}{x(x+1)} ; x \ne 0,-1;$
$=\frac{-3}{x(x+1)}; x\ne 0,-1;$
College Algebra (6th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-32178-228-3
ISBN 13:
978-0-32178-228-1
Chapter P - Prerequisites: Fundamental Concepts of Algebra - Exercise Set P.6 - Page 86: 43
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