College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter P - Prerequisites: Fundamental Concepts of Algebra - Exercise Set P.6: 35

Answer

$\frac{2x-1}{x+3} ;x \ne 0,-3$

Work Step by Step

$\frac{x^{2}-2x}{x^{2}+3x}+ \frac{x^{2}+x}{x^{2}+3x}$ Denominator is the same, so add the numerator. $= \frac{x^{2}-2x+x^{2}+x}{x^{2}+3x}$ Combine like terms. $=\frac{ 2x^{2} -x }{x^{2}+3x}$ Take out common factors. Exclude 0, -3 for non-zero denominators. $=\frac{ x(2x -1) }{x(x+3)};x \ne 0,-3$ Divide out common factors. $=\frac{2x-1}{x+3} ;x \ne 0,-3$
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