Answer
$\frac{29}{6(x+4)}; x \ne -4;$
Work Step by Step
$\frac{5}{(2x+8)} + \frac{7}{(3x+12)}$
Take out common factor from the denominator,
$=\frac{5}{2(x+4)} + \frac{7}{3(x+4)}$
Taking LCD, the denominator becomes $[2 \times 3 \times (x+4) = 6(x+4)]$ and the expression becomes
$=\frac{5(3) + 7(2)}{6(x+4)}; x \ne -4;$
$=\frac{15 + 14}{6(x+4)}; x \ne -4;$
$=\frac{29}{6(x+4)}; x \ne -4;$
