Answer
5 and -5
Work Step by Step
We need to factor the denominator first in order to assist in determining what the domain is:
$\frac{x+5}{(x+5)(x-5)}$
Note that the $x+5$ term cancels; even so, since it is still in the denominator initially, it still remains a domain restriction.
Set each term in the denominator equal to 0 in order to ascertain the domain restrictions:
$x + 5 = 0$ and $x - 5 = 0$
$x = -5$ and $x = 5$
Therefore, -5 and 5 are numbers restricted from the domain, as they make the denominator zero.
