College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 8 - Summary, Review, and Test - Test - Page 791: 7



Work Step by Step

$_{n}C_k=\frac{n!}{(n-k)!k!}$ Hence here: $_{10}C_3=\frac{10!}{3!(10-3)!}=\frac{10\cdot9\cdot8}{3\cdot2\cdot1}=120$
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