Answer
$120$
Work Step by Step
$_{n}C_k=\frac{n!}{(n-k)!k!}$
Hence here: $_{10}C_3=\frac{10!}{3!(10-3)!}=\frac{10\cdot9\cdot8}{3\cdot2\cdot1}=120$
College Algebra (6th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-32178-228-3
ISBN 13:
978-0-32178-228-1
Chapter 8 - Summary, Review, and Test - Test - Page 791: 7
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