College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 8 - Summary, Review, and Test - Test - Page 791: 22

Answer

$\frac{3}{5}$

Work Step by Step

"Does not have brown eyes" $=$ males or females that have either blue and green eyes. Let $P =$ probability of a student that does not have brown eyes $P = \frac{number of students with blue and green}{total number of students}$ $= \frac{18 + 10 + 20 + 12}{22 + 18 + 10 + 18 + 20 + 12}$ $= \frac{60}{100}$ $= \frac{6}{10}$ $=\frac{3}{5}$
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