College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 8 - Summary, Review, and Test - Test - Page 791: 2

Answer

$105$

Work Step by Step

$\sum_{i=1}^{5} (i^2+10)=(1^2+10)+(2^2+10)+(3^2+10)+(4^2+10)+(5^2+10)=(1+10)+(4+10)+(9+10)+(16+10)+(25+10)=11+14+19+26+35=105$
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