College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 8 - Summary, Review, and Test - Test - Page 791: 5

Answer

$36$

Work Step by Step

${n \choose k}=\frac{n!}{k!(n-k)!}$ Hence here: ${9 \choose 2}=\frac{9!}{2!(9-2)!}=\frac{9\cdot8}{2}=36$
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