College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 8 - Summary, Review, and Test - Test - Page 791: 24

Answer

$P = \frac{3}{5}$

Work Step by Step

"is a female or has green eyes" = selecting a student that is a female with any eye color OR is either a male/female with green eyes. Let $P = $ probability of selecting a student that is a female or has green eyes $P = \frac{(number of females)+(number of male/females with green eyes)}{100}$ $= \frac{(18+20+12)+(10)}{100}$ (Notice we didn't count 12 females with green eyes as you only consider them ONE time in the brackets "number of females") $= \frac{50+10}{100}$ $= \frac{60}{100}$ $= \frac{3}{5}$
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