College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 8 - Summary, Review, and Test - Test - Page 791: 19

Answer

$990$

Work Step by Step

If we want to choose $k$ elements out of $n$ regarding the order, not allowing repetition, we can do this in $_{n}P_k=\frac{n!}{(n-k)!}$ ways. The order matters here when choosing the three people, thus we have to use permutations. We have $11$ people for $3$ spots, thus $_{11}P_{3}=\frac{11!}{(11-3)!}=990$
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