Answer
$990$
Work Step by Step
If we want to choose $k$ elements out of $n$ regarding the order, not allowing repetition, we can do this in $_{n}P_k=\frac{n!}{(n-k)!}$ ways.
The order matters here when choosing the three people, thus we have to use permutations. We have $11$ people for $3$ spots, thus $_{11}P_{3}=\frac{11!}{(11-3)!}=990$