Answer
$P = \frac{39}{50}$
Work Step by Step
"Has brown eyes or blue eyes" = probability of selecting a student with either brown or blue eyes but NOT green eyes.
Let $P = $ probability of selecting a student with brown or blue eyes
$P = \frac{number of students with brown and blue eyes}{total number of students}$
$P = \frac{22+18+18+20}{100}$
$= \frac{78}{100}$
$= \frac{39}{50}$
