College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 6 - Summary, Review, and Test - Review Exercises - Page 657: 52

Answer

$x=\dfrac{7}{4}$ $y=-\dfrac{25}{8}$

Work Step by Step

First we have to compute the determinants $D,D_x,D_y$: $D=\begin{vmatrix}1&-2\\3&2\end{vmatrix}=2+6=8$ $D_x=\begin{vmatrix}8&-1\\3&2\end{vmatrix}=16-2=14$ $D_y=\begin{vmatrix}1&8\\3&-1\end{vmatrix}=-1-24=-25$ We use Cramer's Rule to determine the solutions of the system: $x=\dfrac{D_x}{D}=\dfrac{14}{8}=\dfrac{7}{4}$ $y=\dfrac{D_y}{D}=\dfrac{-25}{8}=-\dfrac{25}{8}$ The solution is: $x=\dfrac{7}{4}$ $y=-\dfrac{25}{8}$
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