College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 6 - Summary, Review, and Test - Review Exercises - Page 657: 31

Answer

$\begin{bmatrix} -2&0&0\\1&1&-3\end{bmatrix}$

Work Step by Step

The matrix of the initial triangle's coordinates is: $B=\begin{bmatrix}0&2&2\\0&0&-4\end{bmatrix}$ In order to move the triangle 2 units left, we must subtract 2 from each $x$-coordinate. In order to move the triangle 1 unit up, we must add 1 to each $y$-coordinate. The change matrix is: $T=\begin{bmatrix} -2&-2&-2\\1&1&1\end{bmatrix}$ Determine the new coordinates: $B+T=\begin{bmatrix}0&2&2\\0&0&-4\end{bmatrix}+\begin{bmatrix} -2&-2&-2\\1&1&1\end{bmatrix}$ $=\begin{bmatrix} 0-2&2-2&2-2\\0+1&0+1&-4+1\end{bmatrix}$ $=\begin{bmatrix} -2&0&0\\1&1&-3\end{bmatrix}$
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