College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 4 - Summary, Review, and Test - Review Exercises - Page 511: 73

Answer

$x = 1.10$

Work Step by Step

$e^{2x} - e^{x} - 6 = 0$ Let $e^{x} = x$ $x^{2} - x - 6 = 0$ $(x-3)(x+2) = 0$ $e^{x} - 3 = 0$ $e^{x} = 3$ $x = \ln 3$ $e^{x} + 2 = 0$ $e^{x} = -2$ $x \ne \ln (-2)$ Therefore, $x = \ln 3=1.10$
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