College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 4 - Summary, Review, and Test - Review Exercises - Page 511: 45

Answer

$\sqrt{x}$

Work Step by Step

Using the Basic Logarithmic Property $b^{\log_{b}x}=x$ (here, ln is $\log_{e})$ $e^{\ln\sqrt{x}}=e^{\log_{e}\sqrt{x}} =\sqrt{x}$
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