College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 4 - Summary, Review, and Test - Review Exercises - Page 511: 51

Answer

$= \frac{1}{2}\log_4 x - 3$

Work Step by Step

$= \log_4 (\frac{\sqrt x}{64})$ $= \log_4 \sqrt x - \log_4 64$ $= \log_4 x^{\frac{1}{2}} - \log_4 (4)^{3}$ $= \frac{1}{2}\log_4 x - 3$
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