College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 4 - Summary, Review, and Test - Review Exercises - Page 511: 56

Answer

$= \ln ({x^{3}}{y^{4}})$

Work Step by Step

$= 3 \ln x + 4\ln y$ $= \ln x^{3} + \ln y^{4}$ $= \ln ({x^{3}}{y^{4}})$
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