College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 4 - Summary, Review, and Test - Review Exercises - Page 511: 43

Answer

domain: $(-\infty,1)\cup(1, \infty)$

Work Step by Step

The restriction for the domain of a logarithmic function is that its argument must be positive. Domain: all $x$ for which $(x-1)^{2}>0$ Now, the square of a number is never negative, so the only problem is when it is 0. domain: $x\neq 1$ In interval notation, domain: $(-\infty,1)\cup(1, \infty)$
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