College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 4 - Summary, Review, and Test - Review Exercises - Page 511: 69

Answer

$x = 0.99$

Work Step by Step

$9e^{5x} = 1269$ $e^{5x} = \frac{1269}{9}$ $e^{5x} = 141$ $5x = \ln 141$ $x = \frac{\ln 141}{5}$ $x = 0.99$
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