#### Answer

$-2, 10, 22, 34, 46$

#### Work Step by Step

$\bf{\text{Solution Outline:}}$
To find the first $5$ terms, keep adding the given common difference to the given first term.
$\bf{\text{Solution Details:}}$
In the given sequence, $a_1=
-2
,$ and $d=
12
.$ Then the second term is
\begin{array}{l}\require{cancel}
a_2=a_1+d
\\\\
a_2=-2+12
\\\\
a_2=10
,\end{array}
the third term is
\begin{array}{l}\require{cancel}
a_3=a_2+d
\\\\
a_3=10+12
\\\\
a_3=22
,\end{array}
the fourth term is
\begin{array}{l}\require{cancel}
a_4=a_3+d
\\\\
a_4=22+12
\\\\
a_4=34
,\end{array}
and the fifth term is
\begin{array}{l}\require{cancel}
a_5=a_4+d
\\\\
a_5=34+12
\\\\
a_5=46
,\end{array}
Hence, the first $5$ terms are $
-2, 10, 22, 34, 46
.$