College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 7 - Section 7.2 - Arithmetic Sequences and Series - 7.2 Exercises - Page 645: 35

Answer

$S_{10}=230$

Work Step by Step

$\bf{\text{Solution Outline:}}$ To find $S_{10}$ in the given sequence \begin{array}{l}\require{cancel} 5,9,13,... \end{array} use the formula for finding the sum of the first $n$ terms of an arithmetic sequence. $\bf{\text{Solution Details:}}$ The common difference, $d,$ of an arithmetic sequence is the difference of a term and the term preceeding it. Hence, the common difference of the given sequence is \begin{array}{l}\require{cancel} d=a_2-a_1 \\\\ d=9-5 \\\\ d=4 .\end{array} Using the formula for the sum of the first $n$ terms of an airthmetic sequence, which is given by $ S_n=\dfrac{n}{2}[2a_1+(n-1)d] ,$ then the sum of the first $n=10$ terms with $a_1=5$ and $d=4$ is \begin{array}{l}\require{cancel} S_n=\dfrac{n}{2}[2a_1+(n-1)d] \\\\ S_{10}=\dfrac{10}{2}[2\cdot5+(10-1)4] \\\\ S_{10}=5[10+(9)4] \\\\ S_{10}=5[10+36] \\\\ S_{10}=5[46] \\\\ S_{10}=230 .\end{array}
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