College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 7 - Section 7.2 - Arithmetic Sequences and Series - 7.2 Exercises - Page 645: 26

Answer

$a_1=10$

Work Step by Step

Sum formula: $$S_n=\frac n2(a_1+a_n)$$ Use $n=16$: $$S_{28}=\frac {28}2(a_1+a_{28})$$ Substitute $S_{28}=2926$ and $a_{28}=199$: $$2926=\frac {28}2(a_1+199)$$ Solve for $a_1$: $$2926=14(a_1+199)$$ $$a_1+199=209$$ $$a_1=10$$
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