Answer
$a_1=5$
Work Step by Step
Sum formula:
$$S_n=\frac n2(a_1+a_n)$$
Use $n=16$:
$$S_{16}=\frac {16}2(a_1+a_{16})$$
Substitute $S_{16}=-160$ and $a_{16}=-25$:
$$-160=\frac {16}2(a_1+(-25))$$
Solve for $a_1$:
$$-160=8(a_1-25)$$
$$a_1-25=-20$$
$$a_1=5$$