#### Answer

$4, 7, 10, 13, 16$

#### Work Step by Step

$\bf{\text{Solution Outline:}}$
To find the first $5$ terms, keep adding the given common difference to the given first term.
$\bf{\text{Solution Details:}}$
In the given sequence, $a_1=
4
,$ and $d=
3
.$ Then the second term is
\begin{array}{l}\require{cancel}
a_2=a_1+d
\\\\
a_2=4+3
\\\\
a_2=7
,\end{array}
the third term is
\begin{array}{l}\require{cancel}
a_3=a_2+d
\\\\
a_3=7+3
\\\\
a_3=10
,\end{array}
the fourth term is
\begin{array}{l}\require{cancel}
a_4=a_3+d
\\\\
a_4=10+3
\\\\
a_4=13
,\end{array}
and the fifth term is
\begin{array}{l}\require{cancel}
a_5=a_4+d
\\\\
a_5=13+3
\\\\
a_5=16
,\end{array}
Hence, the first $5$ terms are $
4, 7, 10, 13, 16
.$