College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter R - Section R.2 - Algebra Essentials - R.2 Assess Your Understanding - Page 27: 96


$\displaystyle \frac{216x^{6}}{125y^{6}}$

Work Step by Step

We simplify: $(\displaystyle \frac{5x^{-2}}{6y^{-2}})^{-3} =(\frac{5y^{2}}{6x^{2}})^{-3} =(\frac{6x^{2}}{5y^{2}})^{3} =\frac{6^{3}(x^{2})^{3}}{5^{3}(y^{2})^{3}} =\frac{216x^{6}}{125y^{6}}$
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