## College Algebra (10th Edition)

$-\dfrac{1}{16}$
The given expression is equivalent to $-(4^{-2})$ RECALL: $a^{-m} = \dfrac{1}{a^m}, a \ne 0$ Use the rule above to obtain: $-(4^{-2}) = -(\dfrac{1}{4^2})=-(\dfrac{1}{16})=-\dfrac{1}{16}$