College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter R - Section R.2 - Algebra Essentials - R.2 Assess Your Understanding - Page 27: 78



Work Step by Step

The given expression is equivalent to $-(4^{-2})$ RECALL: $a^{-m} = \dfrac{1}{a^m}, a \ne 0$ Use the rule above to obtain: $-(4^{-2}) = -(\dfrac{1}{4^2})=-(\dfrac{1}{16})=-\dfrac{1}{16}$
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