## College Algebra (10th Edition)

$25^oC$
Substitute the given temperature value for $F$ in the given formula to obtain: $\require{cancel} C = \frac{5}{9}(77-32) \\C=\frac{5}{9}(45) \\C=\frac{5}{\cancel{9}}(\cancel{45}5) \\C=25$ Thus, $77^oF = 25^oC$