College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter R - Section R.2 - Algebra Essentials - R.2 Assess Your Understanding - Page 27: 66



Work Step by Step

RECALL: The denominator of a rational expression is not allowed to be equal to zero since division of zero is undefined. Factor the denominator to obtain: $\dfrac{-9x^2-x+1}{x^3+x} = \dfrac{-9x^2-x+1}{x(x^2+1)}$ Find the values of $x$ that will make the denominator equal to zero by using the zero-factor theorem. Equate each factor of the denominator to zero then solve each equation to obtain: $\begin{array}{ccc} \\&x = 0 &\text{ or } &x^2+1 = 0 \\&x=0 &\text{ or } &x^2=-1 \\\end{array}$ No real number satisfies the second equation. Thus, in the given expression, $x$ cannot be equal to $0$ since it will make the denominator equal to 0. Therefore, the answer is: $(c)$.
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