College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter R - Section R.2 - Algebra Essentials - R.2 Assess Your Understanding - Page 27: 72



Work Step by Step

Substitute the given temperature value to $F$ in the given formula to obtain: $\require{cancel} C = \frac{5}{9}(212-32) \\C=\frac{5}{9}(180) \\C=\frac{5}{\cancel{9}}(\cancel{180}20) \\C=100$ Thus, $212^oF = 100^oC$
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