College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter R - Section R.2 - Algebra Essentials - R.2 Assess Your Understanding - Page 27: 93


$\displaystyle -\frac{8x^{3}z}{9y}$

Work Step by Step

We simplify: $\displaystyle \frac{(-2)^{3}x^{4}(yz)^{2}}{3^{2}xy^{3}z}=\frac{-8x^{4}y^{2}z^{2}}{9xy^{3}z^1} =-\frac{8}{9}x^{4-1}y^{2-3}z^{2-1} =-\frac{8}{9}x^{3}y^{-1}z^{1} =-\frac{8x^{3}z}{9y}$
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