College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter R - Section R.2 - Algebra Essentials - R.2 Assess Your Understanding - Page 27: 94


$\displaystyle \frac{1}{2x^{6}y^{2}z}$

Work Step by Step

We simplify: $\displaystyle \frac{4x^{-2}(yz)^{-1}}{2^{3}x^{4}y}= \frac{4x^{-2}y^{-1}z^{-1}}{8x^{4}y^1} =\frac{4}{8}x^{-2-4}y^{-1-1}z^{-1} =\frac{1}{2}x^{-6}y^{-2}z^{-1} =\frac{1}{2x^{6}y^{2}z}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.