## College Algebra (10th Edition)

$a_n=\dfrac{1}{n(n+1)}$
The pattern shows that: (1) The numerator is always 1. (2) The denominators involve the product of two numbers: the term number $n$ and the next integer $n+1$. Thus, the $n^{th}$ term of the sequence is: $a_n=\dfrac{1}{n(n+1)}$