Answer
The first five terms are:
$a_1 = \dfrac{1}{3};
\\a_2= \dfrac{1}{2};
\\a_3= \dfrac{3}{5};
\\a_4= \dfrac{2}{3};
\\a_5= \dfrac{5}{7}$
Work Step by Step
The term is equal to $\dfrac{n}{n+2}$.
For each term that is in the sequence, we plug in the given value for $n$:
$a_1 = \dfrac{1}{1+2} = \dfrac{1}{3};
\\a_2= \dfrac{2}{2+2} = \dfrac{2}{4} = \dfrac{1}{2};
\\a_3= \dfrac{3}{3+2} = \dfrac{3}{5};
\\a_4= \dfrac{4}{4+2} = \dfrac{4}{6} = \dfrac{2}{3};
\\a_5= \dfrac{5}{5+2} = \dfrac{5}{7}$
