Answer
The first five terms are:
$b_1 = \dfrac{3}{2};
\\b_2= \dfrac{5}{4};
\\b_3= \dfrac{7}{6};
\\b_4= \dfrac{9}{8};
\\b_5= \dfrac{11}{10}$
Work Step by Step
The term is equal to $\dfrac{2n+1}{2n}$.
For each term that is in the sequence, we plug in the given value for $n$:
$b_1 = \dfrac{2(1)+1}{2(1)} = \dfrac{3}{2};
\\b_2= \dfrac{2(2)+1}{2(2)} = \dfrac{5}{4};
\\b_3= \dfrac{2(3)+1}{2(3)} = \dfrac{7}{6};
\\b_4= \dfrac{2(4)+1}{2(4)} = \dfrac{9}{8};
\\b_5= \dfrac{2(5)+1}{2(5)} = \dfrac{11}{10}$
