Answer
The first five terms are:
$c_1 = \dfrac{1}{2};
\\c_2= 1;
\\c_3= \dfrac{9}{8};
\\c_4= 1;
\\c_5= \dfrac{25}{32}$
Work Step by Step
Substitute $n=1, 2, 3, 4, 5$ to obtain:
$c_1 = \dfrac{1^2}{2^1}=\dfrac{1}{2};
\\c_2= \dfrac{2^2}{2^2}=1;
\\c_3= \dfrac{3^2}{2^3}=\dfrac{9}{8};
\\c_4= \dfrac{4^2}{2^4}=\dfrac{16}{16}=1;
\\c_5= \dfrac{5^2}{2^5}=\dfrac{25}{32}$
