## College Algebra (10th Edition)

$s_1 = \dfrac{4}{3}; \\s_2= \dfrac{16}{9}; \\s_3= \dfrac{64}{27}; \\s_4= \dfrac{256}{81}; \\s_5= \dfrac{1024}{243}$
Substitute $n=1, 2, 3, 4, 5$ to obtain: $s_1 = \left(\dfrac{4}{3}\right)^1=\dfrac{4}{3}; \\s_2= \left(\dfrac{4}{3}\right)^2=\dfrac{16}{9}; \\s_3= \left(\dfrac{4}{3}\right)^3=\dfrac{64}{27}; \\s_4= \left(\dfrac{4}{3}\right)^4=\dfrac{256}{81}; \\s_5= \left(\dfrac{4}{3}\right)^5=\dfrac{1024}{243}$